(x/2)^2+(x-2)^2=x^2

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Solution for (x/2)^2+(x-2)^2=x^2 equation: 



(x/2)^2+(x-2)^2=x^2

We move all terms to the left:

(x/2)^2+(x-2)^2-(x^2)=0

determiningTheFunctionDomain
-x^2+(x/2)^2+(x-2)^2=0

We add all the numbers together, and all the variables

-x^2+(+x/2)^2+(x-2)^2=0

We add all the numbers together, and all the variables

-1x^2+(+x/2)^2+(x-2)^2=0

We multiply all the terms by the denominator


-1x^2*2)^2+(+x+((x-2)^2)*2)^2=0

Wy multiply elements

-2x^3+x+((x-2)^2)*2)^2=0

We do not support expression: x^3

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